FACTORING a POLYNOMIAL PRACTICE SHEET 5
The below questions are based on splitting the middle term, common factor
and identity/formula methods.
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ROMAN NUMERALS 201 TO 300
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Factoring a polynomial practice sheet 5 DOUBTS :--
ReplyDeleteQ89, Q91, Q97, Q99
q 91. 8(a+1)sq.+2(a+1)(b+2)-15(b+2)sq
Deletetaking (a+1)=y (b+2)=z
therefore 8(y)Sq+2(y)(z)-15(z)sq
8ySQ+2yz-15ySQ
doing middle term factorisation
8ySQ+12yz-10yz-15zSQ
(4y-5z)(2y+3z)
now putting orginal value ....
y=a+1
z=b+2
{4(a+1)-5(b+2)}{2(b+2)+3(a+1)}
(4a+4-5b-10)(2b+4+3a+3)
ans.(4a-6-5b)(2b+7+3a)
not sure abt ans
sumit bhadra class 9 avte group c
q 91. 8(a+1)sq.+2(a+1)(b+2)-15(b+2)sq
ReplyDeletetaking (a+1)=y (b+2)=z
therefore 8(y)Sq+2(y)(z)-15(z)sq
8ySQ+2yz-15ySQ
doing middle term factorisation
8ySQ+12yz-10yz-15zSQ
(4y-5z)(2y+3z)
now putting orginal value ....
y=a+1
z=b+2
{4(a+1)-5(b+2)}{2(b+2)+3(a+1)}
(4a+4-5b-10)(2b+4+3a+3)
ans.(4a-6-5b)(2b+7+3a)
not sure abt ans
sumit bhadra class 9 avte group c
vipin sir it is right
correct :)
Deletesir im not able to do 81,83,97,99
ReplyDeleteQ81) a sq - b sq - a - b
ReplyDelete(a-b)(a+b)- (a+b)
(a+b)[(a-b)-1] = Answer
awesome :)
DeleteCool! Looks confusing for me but you've found some way to answer this. Thanks!
ReplyDelete