Important word problems on Linear Equations in two variables 7
Question for practice
*Questions:7. A man’s age is 125% of what it was 10 years ago, but (250/3)% of what it will be after 10 years. What is his present age?
The following questions are more helpful for class tenth students for all boards.
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*HOTS
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ReplyDeleteLet man's present age = x years
ReplyDeletex = 125/100(x-10)
or x = 5/4 (x-10)
or x = 5x-50/4 ....(1)
x = 250/300(x+10)
or x = 5/6 (x+10)
or x = 5x+50/6 ....(2)
by comparing (1) and (2),
5x-50/4 = 5x+50/6
or 30x-300 = 20x+200
or 10x = 500
or x = 50
therefore, Man's present age = 50 years.
correct ..
Deletetry the next one :)
LET THE MAN'S AGE BE= x
ReplyDeletex=125/100(x-10)
x=5/4(x-10)
4x=5x-50
therefore,x=50
SO,THE PRESENT AGE OF THE MAN IS 50 YEARS.
hiiii
Deleteruchita dua u have not consider (250/3)% i think so
ia lalso dne tlike ur method
try this http://mevipinsetia.blogspot.in/2012/08/questions-for-linear-equation-word_13.html
Deletesimple way//// easy .....
ReplyDeleteLET THE MAN'S AGE BE= x years
=> x=125/100(x-10)
=> x=5/4(x-10)
=> 4*x=5*x-5*10
=> 4x=5x-50
=> 4x-5x= -50
=> -x= -50
=> x = 50
=> therefore,man's present age is 50 YEARS.
correct ..
Deletetry the next one :)
Let mans age 10 years age = x yrs
ReplyDeletex+10=125/100x
100x+1000=125x
25x=1000x=40
* mans present age = 10+x=10+40=50
let the age of man be x yrs.
ReplyDeleteso,
x=125/100(x-10)
x=5/4(x-10)
4x=5x-50
-x=-50
x=50
therefore, present age of man is 50 yrs.
Here, since only 1 criterion is given i.e. a man's age, hence we will use only 1 variable... and cross check it with both conditions...
ReplyDeleteLet the man's present age be x years
So, x = [125 (x-10)]/100
=> x = [5x - 50]/4
=> 4x = 5x - 50
=> x = 50........(1)
So, one value of x is 50...
CROSS CHECK:-
x = [250/3(100)].(x + 10)
=> x = [5(x+10)]/6
=> 6x = 5x + 50
=> x = 50..........(2)
Since (1) = (2)
Hence the value of x is 50!!!
THANKS!!!