Important word problems on Linear Equations in two variables 11
Question for practice
The following questions are more helpful for class tenth students for all boards.
Questions 11. 10 years ago, Hunny was half of Bunny in age. If the ratio of their present ages is 3 : 4. What will be the total of their present ages?
Submit your answer here or wait for answer
The following questions are more helpful for class tenth students for all boards.
Questions 11. 10 years ago, Hunny was half of Bunny in age. If the ratio of their present ages is 3 : 4. What will be the total of their present ages?
Submit your answer here or wait for answer
This comment has been removed by the author.
ReplyDeletethe sum of their ages is 35 years
Deleteage of bunny is 15 years and of bunny is 20 years
sol.
let present age of hunny be x
n of bunny be y
x-10/y-10 = 1/2
so, 2x-y = 10 (i)
x/y = 3/4 (g)
so, 4x-3y = 0 (ii)
from (i)and (ii)
by elimination, y = 20
hence, x = 15
This comment has been removed by the author.
ReplyDeleteans. let hunny's age = x years
ReplyDeletelet bunny's age = y years
(x-10)=1/2(y-10)
or x-10 = (y-10)/2
or 2(x-10) = y-10
or 2x-20 = y-10
or 2x-y = 10 ...........(1)
x/y = 3/4
or 4x = 3y
or 4x-3y = 0 ............(2)
by elimination from (1) and (2),
x = 15
2(15)-y = 10
or y = 20
therefore , hunny's present age = 15 years
bunny's present age = 20 years
total of their present ages = 15 +20 = 35 years .
This comment has been removed by the author.
ReplyDeletelet present age of hunny be x
ReplyDeleteage of bunny be y
x-10/y-10 = 1/2
so, 2x-y = 10 (1)
x/y = 3/4
4x-3y = 0 (2)
by eliminating (1) and (2)
y = 20 x = 15
therefore , hunny's present age = 15 years
bunny's present age = 20 years
total of their present ages = 15 +20 = 35 years .